Skip to main content

Memcached

Memcached is a high-performance, distributed memory object caching system, generic in nature, but originally intended for  use in speeding up dynamic web application by alleviating database load.

Memcached server is an in memory cache that stores anything from binary to text to primitives associated with a key as key-Value pair.  You saves a lot of load of your backend systems, leading to high scalability. since the data is stored in memory, it is generally faster than making an expensive backend call too.

Limitation:
The key in memcached should be less than 255 chars and each value shouldn't exceed 1MB

What it does?
Memcached allows you to take memory from parts of your system where you have more than you need and make it accessible to areas where you have less than you need. With memcached, you can see that all of the servers are looking into the same virtual pool of memory. This means that a given item is always stored and always retrieved from the same location in you entire web cluster.
Before : each node is completely independent(64M+ 64M = 64M)
after using: each node can make use of memory from other nodes(64M+64M=128M)

How to use memcached?
step 1: install

. Install Libevent( Memcached uses the Libevent library for network IO.)
.  Install Memcached

Step 2: Run memcached:
memcached -d -m 512 127.0.0.1 -p 1121
you can test it by : telnet localhost 11211

Step 3: Client
Generally you can use caching wherever there is bottleneck.
MemcachedClient client = new MemcachedClient(new InetSocketAddress("127.0.0.1",11211);
c.set("someKey",3600,someObject);
Object myObject = client.get("someKey");
client.delete("someKey");








Comments

Popular posts from this blog

Quicksort implementation by using Java

 source: http://www.algolist.net/Algorithms/Sorting/Quicksort. The divide-and-conquer strategy is used in quicksort. Below the recursion step is described: 1st: Choose a pivot value. We take the value of the middle element as pivot value, but it can be any value(e.g. some people would like to pick the first element and do the exchange in the end) 2nd: Partition. Rearrange elements in such a way, that all elements which are lesser than the pivot go to the left part of the array and all elements greater than the pivot, go to the right part of the array. Values equal to the pivot can stay in any part of the array. Apply quicksort algorithm recursively to the left and the right parts - the previous pivot element excluded! Partition algorithm in detail: There are two indices i and j and at the very beginning of the partition algorithm i points to the first element in the array and j points to the last one. Then algorithm moves i forward, until an element with value greater or equal

Live - solving the jasper report out of memory and high cpu usage problems

I still can not find the solution. So I summary all the things and tell my boss about it. If any one knows the solution, please let me know. Symptom: 1.        The JVM became Out of memory when creating big consumption report 2.        Those JRTemplateElement-instances is still there occupied even if I logged out the system Reason:         1. There is a large number of JRTemplateElement-instances cached in the memory 2.     The clearobjects() method in ReportThread class has not been triggered when logging out Action I tried:      About the Virtualizer: 1.     Replacing the JRSwapFileVirtualizer with JRFileVirtualizer 2.     Not use any FileVirtualizer for cache the report in the hard disk Result: The japserreport still creating the a large number of JRTemplateElement-instances in the memory        About the work around below,      I tried: item 3(in below work around list) – result: it helps to reduce  the size of the JRTemplateElement Object        

Stretch a row if data overflows in jasper reports

It is very common that some columns of the report need to stretch to show all the content in that column. But  if you just specify the property " stretch with overflow' to that column(we called text field in jasper report world) , it will just stretch that column and won't change other columns, so the row could be ridiculous. Haven't find the solution from internet yet. So I just review the properties in iReport one by one and find two useful properties(the bold  highlighted in example below) which resolve the problems.   example: <band height="20" splitType="Stretch" > <textField isStretchWithOverflow="true" pattern="" isBlankWhenNull="true"> <reportElement stretchType="RelativeToTallestObject" mode="Opaque" x="192" y="0" width="183" height="20"/> <box leftPadding="2"> <pen lineWidth="0.25"/>